Answer:
Step-by-step explanation:
[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\mathrm{For\:}\quad a=5,\:b=20,\:c=-7:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:5\left(-7\right)}}{2\cdot \:5}\\x=\frac{-20+\sqrt{20^2-4\cdot \:5\left(-7\right)}}{2\cdot \:5}:\quad \frac{-10+3\sqrt{15}}{5}\\x=\frac{-20-\sqrt{20^2-4\cdot \:5\left(-7\right)}}{2\cdot \:5}:\quad -\frac{10+3\sqrt{15}}{5}\\[/tex]
[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\x=\frac{-10+3\sqrt{15}}{5},\:x=-\frac{10+3\sqrt{15}}{5}[/tex]
Answer:
the answers are b, c, d!
Step-by-step explanation:
just took the test on edge2020 :)
