Rewrite the expression in the form a^n help

Answer:
[tex]a^{-\frac{2}{3}}[/tex]
Step-by-step explanation:
[tex]\bigg (a^{\frac{2}{3}}\bigg)^{-1} =\frac{1}{a^{\frac{2}{3}}}} =\huge{\boxed{a^{-\frac{2}{3}}}[/tex]