Respuesta :
Step-by-step explanation:
these number grow by four every time
Y N
1 -2
2 - 6
3- 10
4- 14
N= 4× Y
2= 4 × 1
2= 4
2-4= -2
4× N + -2
4 × 42+ -2
168- -2= 166
Therefore the term of 166 will be 42.
The series of numbers are increasing by a constant amount each term,
making it an arithmetic series or progression.
- The term number that has a value of 166 is the 42nd term
Reasons:
- The first term of the given sequence, a₁ = 2
The difference between the terms are;
- 6 - 2 = 10 - 6 = 14 - 10 = 4
Therefore;
- Each subsequent term has a constant or common difference of , d = 4
- The sequence is an arithmetic progression, and the value of the nth term of the sequence is therefore;
- aₙ = a₁ + (n - 1)·d
Where;
n = The nth term of the sequence
Which gives;
aₓ = 2 + (n - 1)·4 = 166
- (n - 1)·4 = 166 - 2 = 164
[tex]n - 1 = \dfrac{164}{4} = 41[/tex]
Which gives;
n = 41 + 1 = 42
- n = 42
Therefore;
- 166 is the 42nd term of the sequence
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