Q 5) 66.0 square cm
Answer:
Q 6) 58.1 square cm
Step-by-step explanation:
Q 5) Let the radii of exterior and interior circles be R and r.
Therefore, R = 5 cm, r = 5- 3 = 2 cm
Area of the shaded region = Area of the exterior circle - Area of the interior circle
[tex]= \pi R^2 - \pi r^2\\=\pi(R^2-r^2)\\=3.14 (5^2 - 2^2)\\=3.14(25-4)\\=3.14 \times 21\\= 65.94 \: cm^2\\=66.0 \: cm^2\\\\Q\; 6)\\Area\: of\: the\: shaded\: region \\=2\times \frac{180\degree-128\degree}{360\degree} \times \pi r^2\\\\=2\times \frac{52\degree}{360\degree} \times 3.14\times 8^2\\\\= \frac{104}{360} \times 3.14\times 64\\= \frac{20899.84}{360} \\=58.055\\=58.1 \: cm^2[/tex]
