Respuesta :
Answer:
A. The quadratic equation is in standard form
B. Using substitution, the system of equations can be written as 2x^2 - x - 3 = 0
C. There are two real number solutions
The solution of the Jordan's system is [tex]x=-1,x=\frac{3}{2}[/tex]
System of equations :
The given system of equation is,
[tex]y=2x^{2} +3\\\\y-x=6[/tex]
From second equation, [tex]y=6+x[/tex]
Substitute value of y in the first equation.
[tex]2x^{2} +3=6+x\\\\2x^{2} -x-3=0\\\\x^{2} -\frac{1}{2}x-\frac{3}{2} \\\\(x-\frac{3}{2} )(x+1)=0\\\\x=-1,x=\frac{3}{2}[/tex]
The solution of the Jordan's system is [tex]x=-1,x=\frac{3}{2}[/tex]
Learn more about the system of equations here:
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