Jeffery must have at least 97 in his third test in order to have an A average
Mean is the same as average and it is the ratio of the sum of a given sequence of numbers to the sample size. Mathematically;
[tex]Average =\frac{\sum x}{N}[/tex]
x values are the given numbers
N is the sample size
If Jeffery has grades of 93 and 81 on the first two tests of the quarter and he needs a score in the third test for him to have an average of A, then we can assume that an A grade is 90 and the third score is x to have:
[tex]\frac{93 + 81 + x}{3} >90[/tex]
Cross multiply
[tex]93 + 81 + x > 3(90)\\174 + x > 270\\x > 270-174\\x>96\\[/tex]
This shows that Jeffery's score in his last test must be greater than 96 for him to have an A average. Hence Jeffery must have at least 97 in his third test in order to have an A average
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