Answer:
The equation of the line that passes through the points (-6, -8)and (-3, -3) is
5 x - 3 y + 6 =0
Step-by-step explanation:
Step(i):-
Given points are ( -6 ,-8) and ( -3 ,-3)
Slope of the line
[tex]m = \frac{y_{2}-y_{1} }{x_{2} - x_{1} } = \frac{-3+8}{-3+6} = \frac{5}{3}[/tex]
Step(ii):-
Slope -point form
[tex]y-y_{1} =m(x-x_{1} )[/tex]
[tex]y-(-8) =\frac{5}{3} (x-(-6) )[/tex]
cross multiplication, we get
3(y +8 ) = 5(x+6)
3 y +24 = 5 x +30
5 x - 3 y +30 -24 =0
5 x - 3 y + 6 =0
Final answer:-
The equation of the line that passes through the points (-6, -8)and (-3, -3) is
5 x - 3 y + 6 =0
