Answer:
10. Not enough information
11. B ≈ 12.0°
12. A ≈ 34.1°
Step-by-step explanation:
10. Not enough information
11.
We need to use the Law of Sines, which states that for a triangle with lengths a, b, and c and angles A, B, and C:
[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]
Here, we can say that AB = c = 38, C = 128, and AC = b = 10. Plug these in to find B:
[tex]\frac{b}{sinB} =\frac{c}{sinC}[/tex]
[tex]\frac{10}{sinB} =\frac{38}{sin128}[/tex]
Solve for B:
B ≈ 12.0°
12.
Use the Law of Sines as above.
[tex]\frac{a}{sinA} =\frac{b}{sinB}[/tex]
[tex]\frac{23}{sinA} =\frac{28}{sin(43)}[/tex]
Solve for A:
A ≈ 34.1°
