Due to the popularity of instant messaging and social​ networking, informal elements such as emoticons​ (e.g., the symbol​ ":)" to represent a​ smile) and abbreviations​ (e.g., "LOL" for​ "laughing out​ loud") have worked their way into​ teenagers' school writing assignments. A survey interviewed 900 randomly selected teenagers by telephone on their writing habits.​ Overall, 442 of the teenagers admitted using at least one informal element in school writing assignments. Based on the survey​ results, construct a 90​% confidence interval for the proportion of all teenagers who have used at least one informal element in school writing assignments. Give a practical interpretation of the interval.

Respuesta :

Answer:

[tex]0.491 - 1.64\sqrt{\frac{0.491(1-0.491)}{900}}=0.464[/tex]

[tex]0.491 + 1.64\sqrt{\frac{0.491(1-0.491)}{900}}=0.518[/tex]

We are 90% confident that the true proportion of teenagers who have used at least one informal element in school writing assignments is between 0.464 and 0.518

Step-by-step explanation:

We can begin finding the estimator for the proportion of interest:

[tex]\hat p =\frac{442}{900}= 0.491[/tex]

The confidence level is 90% , and the significance level would be given by [tex]\alpha=1-0.90=0.1[/tex] and [tex]\alpha/2 =0.05[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

Replacing the info given we got:

[tex]0.491 - 1.64\sqrt{\frac{0.491(1-0.491)}{900}}=0.464[/tex]

[tex]0.491 + 1.64\sqrt{\frac{0.491(1-0.491)}{900}}=0.518[/tex]

We are 90% confident that the true proportion of teenagers who have used at least one informal element in school writing assignments is between 0.464 and 0.518