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[tex]answers \\ a. \: x = 60 \\ b. \: being \: alternate \: interior \: angles \\ solution \\ all \: sides \: of \: triangle \: are \: equal \\ ab = bc = ac \\ < abc = < acb = < bac = y \\ < abc + < acb + < bac = 180 \\ or \: y + y + y = 180 \\ or \: 3y = 180 \\ or \: y = \frac{180}{3} \\ y = 60 \\ < acb = < cad \\ < cad = x = 60( \: being \: alternate \: interior \: angles) \\ hope \: it \: helps...[/tex]
