[tex]answer = \\ red = 4 \\ blue = 12 \\ green = 16 \\ solution \: \\ let \: the \: ratios \: be \: x \: 3x \: 4x \\ x \ + 3x + 4x = 32 \\ or \: 8x = 32 \\ or \: x = \frac{32}{8} \\ x = 4 \\ replacing \: value \\ 3x \\ = 3 \times 4 \\ = 12 \\ 4x \\ = 4 \times \: 4 \\ = 16 \\ hope \: it \: helps...[/tex]
