Answer:
[tex]\frac{3}{8}[/tex]
Step-by-step explanation:
The outcomes you are looking for are either HTT, THT, or TTH.
The possibility to toss tails or heads is 0.5. Thus the possibility to throw T and then H and then H is:
[tex]\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}[/tex]
We have three ways of getting 2 tails, the possibility of throwing exactly two tails in three tosses is:
[tex]\frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{3}{8}[/tex]
0.375 is the probability of getting exactly 2 tails in 3 tosses.
{0 tails}={HHH}
{1 tails}={TTH, THT, HTT}
{2 tails}={HTT, TTH, THT}
{3 tails}={TTT}
There are 3 cases with getting two tails out of 8 possible outcomes.
