The end behaviour for the polynomial function h(x)=−x3+x4−2x+1 h ( x ) = - x 3 + x 4 - 2 x + 1 is: x→−[infinity], y→−[infinity] x → - [infinity] , y → - [infinity] and x→[infinity], y→[infinity] x → [infinity] , y → [infinity] x→−[infinity], y→[infinity] x → - [infinity] , y → [infinity] and x→[infinity], y→[infinity] x → [infinity] , y → [infinity] x→−[infinity], y→−[infinity] x → - [infinity] , y → - [infinity] and x→[infinity], y→−[infinity] x → [infinity] , y → - [infinity] Unable to tell.

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Newton9022 Newton9022 · Answer 1 · 2020-06-23T02:56:53+02:00

Answer:

[tex]\text{As } x \to \infty, y \to \infty,$and as x \to -\infty, y \to \infty[/tex]

Step-by-step explanation:

Given the polynomial function: [tex]h(x)=-x^3+x^4-2x+1[/tex]

To examine its end behavior, we create a table of values that we can then examine.

[tex]\left|\begin{array}{c|c}x&h(x)\\--&--\\-4&329\\-3&115\\-2&29\\-1&5\\0&1\\1&-1\\2&5\\3&49\\4&185\end{array}\right|[/tex]

From the table, we see a repeating pattern of positive values of h(x) with h(1)=-1 being an axis of symmetry.

Therefore, as:

[tex]x \to \infty, h(x) \to \infty\\x \to -\infty, h(x) \to \infty[/tex]