Imagine an isolated positive point charge Q (many times larger than the charge on a single proton). There is a charged particle A (whose charge is much smaller than charge Q) at a distance from the point charge Q. On which of the following quantities does the magnitude of the electric field created by charge Q at particle A's position depend?a) the amount of the charge on the point charge Qb) the specific location of the charged particle A (while the distance between Q and A is fixed)c) the specific location of the point charge Q (while the distance between Q and A is fixed)d) the type of the charge on the charged particle Ae) the relative orientation between Q and A (while the distance between Q and A is fixed)f) the distance between the point charge Q and the charged particle Ag) the amount of the charge on the charged particle A

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moya1316 moya1316 · Answer 1 · 2020-06-26T02:22:16+02:00

Answer:

b) the specific location of the charged particle A

f) the distance between the point charge Q and the charged particle A

Explanation:

For this exercise we write the electric field

E = k Q / r²

where r is the distance between charge Q and test charge A

Let's examine the different claims

a) do not depend. The charge of the individual is independent of the elective field

b) depends. The position of the particle is different if it has the same distance

c) do not depend. The particle Q must be considered the origin of the coordinate system

d) does not depend. The charge of a particle is independent of the field where it is

e) does not depend. The position of the particle is fixed

f) depends. The field is different for each distance

g) does not depend. The amount of electric charge is independent of the field

okpalawalter8 okpalawalter8 · Answer 2 · 2022-01-25T13:34:41+01:00

The magnitude of the electric field created by charge Q at particle A depends on

because, the directions of the electric field lines for a positive charge and a negative one are just opposite to each - other,

because the direction of the electrostatic force vector just reverses for a reversion of the relative orientation of the charges.

It is simply defined as the force per charge on the test charge.

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