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Question 1
A 10 N block is at the bottom of a frictionless incline as shown to the right. How much work must be done against gravity to move it to the top of the incline?

A)600j

B)1000j

C)4800j

D)800j

Question 1 A 10 N block is at the bottom of a frictionless incline as shown to the right How much work must be done against gravity to move it to the top of the class=

Respuesta :

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

[tex]W=F\times h\\\\W=10\times 60\\\\W=600\ J[/tex]

So, the work done against the gravity is 600 J.

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