Answer:
Scale factor is 3.
Step-by-step explanation:
Given: The Line Segment AB is dilated and a line segment A'B' is created.
A' (0, 6) and B' (6, 9).
As per the given graph , we can easily see that the coordinates of A and B are
A(0, 2) and B(2, 3)
Please refer to attached graph for the coordinates of A', B' and A, B.
The distance formula is given as:
[tex]D =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
D is the distance between two coordinates [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].
So, the distance AB = [tex]\sqrt{(2-0)^2+(3-2)^2} = \sqrt{5}[/tex]
Similary, distance A'B' = [tex]\sqrt{(6-0)^2+(9-6)^2} = \sqrt{36 + 9}=\sqrt{45} = 3\sqrt{5}[/tex]
We can clearly see that A'B' is three times the distance AB.
So, The scale factor 3.
