contestada

The sum of two consecutive integers is -15. If
1 is added to the smaller integer and 2 is
subtracted from the larger integer, what is the
product of the two resulting integers?

PLEASE HELP AND EXPLAIN BECAUSE I DONT GET IT

15 POINTS

Respuesta :

yjacques
Answer:

-16

Step by Step Explanation:

-7 and -8 are consecutive integers.

-7+-8=-15

Add 1 to -7 and you get -6.

Subtract 2 from -8 and you get -10.

-10+-6=-16

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. The product of the two resulting integers is 80.

What is multiplication?

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. For example, 3 × 4 means 3 is added to itself 4 times, and vice versa for the other number.

Let the unknown integer be represented by x. Given that the sum of two consecutive integers is -15. Therefore, we can write,

x + (x+1) = -15

2x + 1 = -15

2x = -16

x = -8

Thus, the smaller integer is -9 and the larger integer is -8.

Now, If 1 is added to the smaller integer and 2 is subtracted from the larger integer.

Smaller Interger = -9 + 1 = -8

Larger Integer = -8 - 2 = -10

Further,  the product of the two resulting integers is,

Product = -8 × -10

             = 80

Hence, the product of the two resulting integers is 80.

Learn more about Multiplication:

https://brainly.com/question/14059007

#SPJ2

Otras preguntas