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Use a one-dimensional array to solve the following problem: A company pays its salespeople on a commission basis. The salespeople receive $200 per week plus 9% of their gross sales for that week. For example, a salesperson who grosses $5,000 in sales in a week receives $200 plus 9% of $5,000, or a total of $650. Write an app (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson's salary is an integer). a) $200–299
b) $300–399
c) $400–499
d) $500–599
e) $600–699
f) $700–799
g) $800–899
h) $900–999
i) $1000 and over
Summarize the results in tabular format.

Respuesta :

Preciousorekha1

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

 

cheers i  hope this helped !!      

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