What are the coordinates of the endpoints of the segment
T'V'?
Triangle TVW is dilated according to the rule
D02(x,y)=(x, y) to create the image triangle T'V"W",
which is not shown.
O T'(-3, 6) and V'(0, 3)
O T'(-3, 6) and V'(0, 1)
O T'(-1, 2) and V'(0,3)
O T'(-1, 2) and V'(0, 1)
0 N
w
2

The given triangle TVW is dilated according to the rule D (3/4)(x,y)=((3/4)x, (3/4)y) to create the image triangle T'V"W", which is not shown.

From the attached image; the coordinates of endpoints T and V are;

T(-4, 8) and V(0, 4)

Therefore, the result segment of the dilation according to the rule; D (3/4)(x,y)=((3/4)x, (3/4)y) is;

T' = 3/4 × (-4, 8) = (-3, 6)

V' = 3/4 × (0, 4) = (0, 3)

What are the coordinates of the endpoints of the segment T'V'? Triangle TVW is dilated according to the rule D02(x,y)=(x, y) to create the image triangle T'V"W", which is not shown. O T'(-3, 6) and V'(0, 3) O T'(-3, 6) and V'(0, 1) O T'(-1, 2) and V'(0,3) O T'(-1, 2) and V'(0, 1) 0 N w 2

Respuesta :

Creating Images on the Cartesian plane

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What are the coordinates of the endpoints of the segment
T'V'?
Triangle TVW is dilated according to the rule
D02(x,y)=(x, y) to create the image triangle T'V"W",
which is not shown.
O T'(-3, 6) and V'(0, 3)
O T'(-3, 6) and V'(0, 1)
O T'(-1, 2) and V'(0,3)
O T'(-1, 2) and V'(0, 1)
0 N
w
2