A company is looking to fill its Board of Directors position. 3 positions will be for men, 2
positions will be for women. There are 16 candidates, 9 men and 7 women. What is the
total possible outcome?

Respuesta :

Answer:

1764 ways

Step-by-step explanation:

Given:

Men = 9

Women = 7

Required Men: 3

Required Women: 2

'

Required

Total Possible Outcome

The total possible outcome can be determine as follows;

Total = (Selection of Men) and (Selection of Women)

Calculating Selection of Men;

Let n represent total number of men; This implies that n = 9;

Let r represent number of men to select; This implies that r = 3;

The selection can be done in the following ways;

[tex]Male = nCr[/tex]

Where [tex]nCr = \frac{n!}{r!(n-r)!}[/tex]

[tex]Male = 9C3[/tex]

[tex]Male = \frac{9!}{3!(9-3)!}[/tex]

[tex]Male = \frac{9!}{3!(6)!}[/tex]

[tex]Male = \frac{9 * 8 * 7 * 6!}{3!6!}[/tex]

[tex]Male = \frac{9 * 8 * 7}{3!}[/tex]

[tex]Male = \frac{9 * 8 * 7}{3*2*1}[/tex]

[tex]Male = 84 ways[/tex]

Calculating Selection of Women;

Let n represent total number of men; This implies that n = 7;

Let r represent number of men to select; This implies that r = 2;

The selection can be done in the following ways;

[tex]Female = nCr[/tex]

Where [tex]nCr = \frac{n!}{r!(n-r)!}[/tex]

[tex]Female = 7C2[/tex]

[tex]Female = \frac{7!}{2!(7-2)!}}[/tex]

[tex]Female = \frac{7!}{2!(5)!}[/tex]

[tex]Female = \frac{7 * 6 * 5!}{2!5!}[/tex]

[tex]Female = \frac{7 * 6}{2!}[/tex]

[tex]Female = \frac{42}{2*1}[/tex]

[tex]Female = 21 ways[/tex]

Recall that

Total = (Selection of Men) and (Selection of Women)

Hence,

[tex]Total = 84 * 21[/tex]

[tex]Total = 1764 ways[/tex]