Respuesta :
Answer:
Using the mid-term break formula for all of them.
a) x²+7x+12
= x²+3x+4x+12
= x(x+3)+4(x+3)
= (x+4)(x+3)
b) x²+6x+8
= x²+2x+4x+8
= x(x+2)+4(x+2)
= (x+4)(x+2)
c) x²+5x+6
= x²+2x+3x+6
= x(x+2)+3(x+2)
= (x=3)(x+2)
d) x²+8x+7
= x²+7x+x+7
= x(x+7)+1(x+7)
= (x+1)(x+7)
Answer:
a) the middle number is seven and the last number is 12
factorising means we want something like (x + ___) (x +__)
Which number go into the blanks?
we need 2 numbers that add together to get 7 multiplied together to get 12.
3 + 4 is equal to 7
3x4=12
Answer:
(x+3)(x+4)
b) the middle number is 6 and the last number is 8
Factoring means we want something like
(x+___)(x+___)
which number go to the blanks?
We need two numbers that add together to get 6 and multiply together to get 8
2+4=6
2x4=8
Answer:
(x+2)(x+4)
c) the middle number is 5 and the last number is 6
we need two numbers that add together to get 5 and multiply together to get 6
2 + 3 is 5 and 2 x 3=6
Answer:
(x+2)(x+3)
Answer:
d) (x+1)(x+7)