Answer:
The pressure that will cause yielding in the tank in the longitudinal direction is 1.7 Mpa
Explanation:
We are dealing with a thin-walled pressure vessel here.
the formula for calculating the hoops stress of this pressure vessel is [tex]\sigma =P d/4t[/tex]
[tex]\sigma Y =[/tex] longitudinal yield stress = [tex]425 \times 10^{6} Pa[/tex]
Thickness = 2/1000 =0.002m
Outside diameter = inside siameter + thickness = Ā 2m + 0.002m= 2.002m
Dm = Mean diameter = Outside diameter - thickness = 2.002 - 0.002 = 2m
[tex]P= 425 \times 10^{6} \times 4 \times 0.002 /2=1.7 Mpa[/tex]
