Answer:
Option D.
Step-by-step explanation:
The vertex form of a parabola along y-axis is
[tex]y=a(x-h)^2+k[/tex]
where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.
The vertex of the parabola is (2,-1). So, h=2 and k=-1.
[tex]y=a(x-2)^2-1[/tex]
The graph passes through (5,0). So,
[tex]0=a(5-2)^2-1[/tex]
[tex]1=9a[/tex]
[tex]\dfrac{1}{9}=a[/tex]
It means coefficient of the squared term is 1/9, which is not the option. So, parabola must be along the x-axis.
The vertex form of a parabola along x-axis is
[tex]x=a(y-k)^2+h[/tex]
where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.
The vertex of the parabola is (2,-1). So, h=2 and k=-1.
[tex]x=a(y+1)^2+2[/tex]
The graph passes through (5,0). So,
[tex]5=a(0+1)^2+2[/tex]
[tex]5-2=a[/tex]
[tex]3=a[/tex]
It means coefficient of the squared term is 3.
Therefore, the correct option is D.
