Respuesta :
Answer:
We conclude that older people are more likely to be victimized.
Step-by-step explanation:
We are given that a survey shows that 10% of the population is victimized by property crime each year.
A random sample of 527 older citizens (65 years or more of age) shows a victimization rate of 12.35%
Let p = population proportion of people who are victimized.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]p \leq[/tex] 10% Â Â Â {means that older people are less likely to be victimized or remains same}
Alternate Hypothesis, [tex]H_A[/tex] : p > 10% Â Â Â {means that older people are more likely to be victimized}
The test statistics that would be used here One-sample z-test for proportions;
               T.S. =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~  N(0,1)
where, [tex]\hat p[/tex] = sample proportion of older people who are victimized = 12.35%
      n = sample of older citizens = 527
So, the test statistics  =  [tex]\frac{0.1235-0.10}{\sqrt{\frac{0.10(1-0.10)}{527} } }[/tex] Â
                    =  1.798
The value of z-test statistics is 1.798.
Since in the question, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for right-tailed test.
Since our test statistics is more than the critical value of z as 1.798 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that older people are more likely to be victimized.