Answer:
The electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Explanation:
Given
[tex]Radius,\ r = 0.03m\\Charge,\ q =7.6\µC[/tex]
Required
Find the electric flux
Electric flux is calculated using the following formula;
Ф = q/ε
Where ε is the electric constant permitivitty
ε [tex]= 8.8542 * 10^{-12}[/tex]
Substitute ε [tex]= 8.8542 * 10^{-12}[/tex] and [tex]q =7.6\µC[/tex]; The formula becomes
Ф = [tex]\frac{7.6\µC}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{6}}[/tex]
Ф = [tex]8.5834970974 *10^{5}}[/tex]
Ф = [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Hence, the electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
