Answer:
13.8 m
Explanation:
Dark fringes are formed in a single slit experiment due to destructive interference that occurs due to interference.
The position of these dark fringes formed on a screen is given by:
[tex]y = \frac{\lambda }{d} (m + 1/2)D[/tex]
where y = position of  mth minimum
m = order of the minimum
D = distance of the slit from the screen
d = width of the slit
λ = wavelength of the light used
We need to find D:
[tex]D = \frac{yd} {\lambda (m + 1/2)} \\[/tex]
From the question:
m = 11
y = 9.85 cm = 0.0985 m
λ  = [tex]6.83 * 10^{-7} m[/tex]
d = 1.11 mm = 0.0011 m
Therefore:
[tex]D = \frac{0.0985 *0.0011} {6.83 * 10^{-7} *(11 + 1/2)} \\\\D = \frac{0.00010835} {6.83 * 10^{-7} * (23/2)} \\\\D = 13.8 m[/tex]
The slit is 13.8 m far from the screen