The directed line segment from L to M has endpoints L(-6,2) and N(5,-3) what are the c and y coordinates of point M which partitions the directed line segment into the ratio 2:5

Respuesta :

Answer:

[tex](-\frac{20}{7},\frac{4}{7})[/tex]

Step-by-step explanation:

Given question is incomplete; here is the complete question.

The directed line segment from L to N has endpoints L(-6,2) and N(5,-3) what are the c and y coordinates of point M which partitions the directed line segment into the ratio 2:5 ?

Segment LM has the endpoints L(-6, 2) and M(5, -3).

A point M which has the coordinates (x, y) divides the segment LM in the ratio of m : n.

Then the coordinates of point M will be,

x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]

and y = [tex]\frac{my_2+ny_1}{m+n}[/tex]

If the given ratio m:n = 2:5

x = [tex]\frac{2(5)+5(-6)}{2+5}[/tex]

  = [tex]\frac{10-30}{2+5}[/tex]

  = -[tex]\frac{20}{7}[/tex]

y = [tex]\frac{2(-3)+5(2)}{2+5}[/tex]

  = [tex]\frac{4}{7}[/tex]

Therefore, coordinates of point M will be [tex](-\frac{20}{7},\frac{4}{7})[/tex]

Answer:

ANSWER

x = - 20}{7}

y={ 4}{7}

Step-by-step explanation: