Answer:
a)0.2240
b)0.5768
Step-by-step explanation:
Given:
µ=3
Poison probability is given by :
[tex]f_k=\frac{\mu^ke^-^\mu}{k!}[/tex]
a) Evaluating at k=3
[tex]f(3)=\frac{3^3e^-^3}{3!} \approx 0.2240[/tex]
b)Evaluating at k=0,1,2:
[tex]f(0)=\frac{3^0e^-^3}{0!} \approx 0.0498[/tex]
[tex]f(1)=\frac{3^1e^-^3}{1!} \approx 0.1494[/tex]
[tex]f(2)=\frac{3^2e^-^3}{2!} \approx 0.2240[/tex]
Use complement rule:
P(x≥3)= 1 - f(0) - f(1) - f(2)= 1- 0.0498 - 0.1494 - 0.2240 =0.5768
