Answer:
[tex]R_s = 0.093 \Omega[/tex]
Explanation:
Voltage of the car battery = 12.0 V
Voltage drop in the battery = 3.4 V
The remainder of the voltage is the starter voltage, that is:
Starter voltage = Initial battery voltage - voltage drop
Starter voltage = 12.0 - 3.4
Starter voltage, [tex]V_{s}[/tex] = 8.6 V
Current drawn by starter, [tex]I_s[/tex] = 93 A
According to Ohm's law: [tex]V_s = I_s R_s[/tex]
Starter Resistance, [tex]R_s[/tex] = [tex]V_s/I_s[/tex]
[tex]R_s = 8.6/93\\R_s = 0.093 \Omega[/tex]
