Answer:
if the resistor is fitted in series with the bulb , then the current flowing will be 0.15 A.....
if the resistor if fitted in parallel with the bulb ,
the current flowing will be 0.6 A
Explanation:
total potential difference = 1.5V
when resistors in series ,
total equivalent resistance is = 5 + 5 = 10 ohm
so current = 1.5 Γ· 10 = 0.15
when resistors in parallel ,
total equivalent resistance is = (5 Γ 5)Γ·(5 + 5) =2.5 ohm
so current = 1.5Γ·2.5 = 0.6 A
