Answer:
aₓ = 0 ,    ay = -6.8125 m / s²
Explanation:
This is an exercise that we can solve with kinematics equations.
Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.
x axis
     vₓ = v₀ₓ = 1.10 m / s
     aₓ = 0
y axis
initially it has no speed, so vâ‚€_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration
     [tex]v_{y}[/tex]= v_{oy} -ay t
     ay = (v_{oy} -v_{y}) / t
     ay = (0 -10.9) / 1.6
     ay = -6.8125 m / s²
the sign indicates that the acceleration goes in the negative direction of the y axis