Answer:
The correct answer will be "22,222 g/sec"
Explanation:
The given values are:
Speed of wing,
[tex]V_{w_{o}}=2.4 \ m/s[/tex]
Stack's height (effective),
[tex]H = 6 \ m[/tex]
Stack's height (measured),
[tex]h = 10 \ m[/tex]
Wood's burning rate,
[tex]r = 400 \ kg/hr[/tex]
Amount of produced CO,
[tex]A=200 \ g[/tex]
Now,
On converting the unit of wood's burning rate, we get
⇒  [tex]r=400 \ kg/hr[/tex]
⇒   [tex]=\frac{400\times 10^3}{60\times 60}[/tex]
⇒   [tex]= 111.11 \ g/sec[/tex]
So that,
The rate of CO production will be:
⇒  [tex]Q=A\times r[/tex]
On putting the estimated values, we get
⇒    [tex]=\frac{200}{1000}\times 111.11[/tex]
⇒    [tex]=22.222 \ g/sec[/tex]
