Answer:
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
Corrected question;
A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.
Explanation:
From the equation of motion;
d = vt + 0.5at^2 .........1
Where;
d = displacement
v = initial velocity = 0
t = time taken= 5 seconds
a = acceleration = 1.9 m/s^2
Substituting the given values into equation 1;
d = 0(5) + 0.5(1.9×5^2)
d = 0.5(1.9×5^2)
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
