Respuesta :
Answer:
The ball will land 12.5m before that hole.
Explanation:
The motion of the golf ball can be considered as a projectile motion, where first its height is 0, then it keeps increasing to a maximum point, after which its height starts decreasing again and hits the ground (height becomes 0 again).
We need to calculate the Range (horizontal distance) of the ball which is given as:
[tex]R=\frac{v_i^2{\cdot}sin2\theta}{g}[/tex]
Where
v(i) = initial velocity = 35 m/s
θ = Initial angle = 35°
g = gravitational acceleration = 9.8 m/s
Substitute in the given formula to find Range:
[tex]R=\frac{(35)^2\cdot{sin}(2)(35)}{9.8}\\R=\frac{(1225)(0.94)}{9.8}\\R = 117.5~m[/tex]
Distance between the hole and position where ball lands = 130m - 117.5m = 12.5m
