Answer:
3/5 v
Explanation:
The computation of speed will the alpha particle have after the collision is shown below:-
In a perfectly elastic the kinetic energy and collision the momentum are considered.
The velocity of the particles defines the below equation:
[tex]VA_f=(\frac{m_A-m_B}{m_A+m_B})VA_i+(\frac{2m_B}{m_A+m_B})VB_i[/tex]
As we know that
[tex]VA_i=v[/tex]
[tex]\\VB_i=0[/tex]
Here, we consider A is the alpha particle and B is the proton and now by the above values we can solve the equation which is below:-
[tex]VA_f=(\frac{4m-m}{4m+m})v[/tex]
[tex]\\VA_f=\frac{3m}{5m}v[/tex]
[tex]\\VA_f=\frac{3}{5}v[/tex]
Therefore the correct answer is [tex]\frac{3}{5}v[/tex]
