Respuesta :
Answer:
(1) Correct option (A).
(2) The probability that Aadi will get Tails is 0.40.
Step-by-step explanation:
The information provided is:
- Eric throws a biased coin 10 times. He gets 3 tails.
- Sue throw the same coin 50 times. She gets 20 tails.
The probability of tail in both cases is:
[tex]P(T|E)=\frac{3}{10}=0.30[/tex]
[tex]P(T|S)=\frac{20}{50}=0.40[/tex]
Here,
P (T|E) implies the probability of tail in case of Eric's experiment.
P (T|S) implies the probability of tail in case of Sue's experiment.
(1)
Now, it is given that Aadi is going to throw the coin once.
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
In this case we need to compute the probability of Aadi getting Tails in a single toss.
As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .
Thus, the correct option is (A).
(2)
As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:
[tex]P(\text{Aadi will get Tails})=P(T|A)[/tex]
                  [tex]=P(T|S)\\\\=0.40[/tex]
Thus, the probability that Aadi will get Tails is 0.40.
Answer:
The correct answer is C and 23/60
Step-by-step explanation:
Sue's estimate is best because she throws it more times than Eric.
This is because the more you throw a coin the more reliable the results will be compared to data from a coin that has been thrown less, therefore the answer is C.
For the second half you need to add the number of tails together to get you numerator and then add the amount of times the coin was thrown to get your denominator, (giving you 23/60)
Hope this helped :)
