Answer:
z^2/(x^3y)
Step-by-step explanation:
We assume you want to simplify ...
[tex]\dfrac{x^{-2}y^0z^2}{xy}=x^{-2-1}y^{0-1}z^2=x^{-3}y^{-1}z^2\\\\=\boxed{\dfrac{z^2}{x^3y}}[/tex]
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Comment on the given expression
What you have written is ...
(x^-2y^0z^2/x)y = yz^2/x^3
The order of operations requires that division and multiplication be done in the order of appearance, so a/xy means (a/x)y unless you put parentheses on the denominator product. Typesetting the expression lets you use the fraction bar for grouping, so parentheses are not needed when that form is used.
