Answer:
f(2)=18
Step-by-step explanation:
This question asks us to find f(2). Basically, it asks us to find f(x) when x is equal to 2.
[tex]f(x)=2(x)^2+5\sqrt{x+2}[/tex]
Therefore, we can substitute 2 in for every x in the equation above.
[tex]f(2)=2(2)^2+5\sqrt{2+2}[/tex]
Solve the exponent first.
2^2=2*2=4
[tex]f(2)=2(4)+5\sqrt{2+2}[/tex]
Next, multiply 2 and 4.
[tex]f(2)=8+5\sqrt{2+2}[/tex]
Next, solve underneath the radical. Add 2 and 2.
[tex]f(2)=8+5\sqrt{4}[/tex]
Next, solve the square root. The square root of 4 is 2.
[tex]f(2)=8+5(2)[/tex]
Multiply 5 and 2.
[tex]f(2)=8+10[/tex]
Finally, add 8 and 10.
[tex]f(2)=18[/tex]
