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Five times the smallest of three consecutive odd integers is seven more than twice
the largest. Find all three consecutive odd integers.

Respuesta :

Answer:

5, 7, 9

Step-by-step explanation:

Using the information given we get:

[tex]5x-7=2z[/tex]

[tex]x+2=y\\y+2=z\\x+4=z[/tex]

[tex]5x-7=2(x+4)\\5x-7=2x+8\\[/tex]

Add 7 to both sides

[tex]5x=2x+15[/tex]

Subtract 2x from both sides

[tex]3x=15[/tex]

Divide both sides by 3

[tex]x=5[/tex]

Using these equations:

[tex]x+2=y\\y+2=z\\x+4=z[/tex]

and

[tex]x=5[/tex]

We get:

[tex]x=5\\y=7\\z=9[/tex]

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