Answer:
The maximum speed is [tex]u = 22 \ m/s[/tex]
Explanation:
From the question we are told that
The distance covered by the debris is [tex]R = 50 \ m[/tex]
The maximum range of the debris projectile is mathematically represented as
[tex]R = \frac{ u^2 sin^2 \theta }{g}[/tex]
At maximum [tex]\theta = 90 ^o[/tex]
Now making u which is the maximum speed at which debris was blown outward by the explosion.
we have
[tex]u = \sqrt{\frac{R * g }{ sin ^2 \theta } }[/tex]
substituting values
[tex]u = \sqrt{\frac{50 * 9.8 }{ [sin 90] ^2} }[/tex]
[tex]u = 22 \ m/s[/tex]
