Answer:
1.3 × 10³ g
Explanation:
Step 1: Convert the mass of calaverite to grams
We will use the relationship 1 kg = 1,000 g.
[tex]3.0kg \times \frac{1,000g}{1kg} = 3.0 \times 10^{3} g[/tex]
Step 2: Establish the appropriate mass ratio
The mass ratio of AuTe₂ to Au is 452.17:196.97.
Step 3: Calculate the maximum mass of pure gold that can be obtained from 3.0 × 10³ g of calaverite
[tex]3.0 \times 10^{3} g Calaverite \times \frac{196.97gAu}{452.17gCalaverite} = 1.3 \times 10^{3} gAu[/tex]
