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The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. The table shows the land area and seismic activity density. A 3-column table has 2 rows. The first column has entries State A, State B. The second column is labeled Land Area (miles squared) with entries 163,696, 10,931. The third column is labeled Seismic Activity Density with entries 0.0299, 0.1402. Which statement about the number of earthquakes the states had for the given time span is true? State A had approximately 1,533 more earthquakes than State B. State B had approximately 1,533 more earthquakes than State A. State A had approximately 3,362 more earthquakes than State B. State B had approximately 3,362 more earthquakes than State A.

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Charmber06

Answer:

State A had approximately 3,362 more earthquakes than State B

Step-by-step explanation:

Let

x-----> the number of earthquakes during a given time span

y ----> the land area affected

z----> seismic activity density of a region

step 1

Find the number of earthquakes during a given time span of State A

we know that

z = x/y

we have

z = 0.0299

y = 163,696mi^2

substitute and solve for x

0.0299 = x/163,696

x = 0.0299 x (163,696) = 4,895\earthquakes

Step 2

Find the number of earthquakes during a given time span of State B

we know that

z = x/y

we have

z=0.1402

y=10,931\ mi^2

substitute and solve for x

0.1402 = x/10,931

x = 0.0299 x (163,696) = 4,895\earthquakes

step 3

Compare the number of earthquakes both states

State A ----> 4,895\ earthquakes

State B ----> 1,533\ earthquakes

Find the difference

4,895 - 1,533 = 3,362\earthquakes

therefore

State A had approximately 3,362 more earthquakes than State B

The seismic activity describes the number of of earthquake that occurs

per square mile.

  • The true statement about the number of earthquakes the states had the given time span is; State A had approximately 3,362 more earthquakes than State B.

Reasons:

The table of values are presented as follows;

[tex]\begin{tabular}{|c|c|c|}&\underline{Land Area (miles squared)}&\underline{Seismic Activity Density} \\State A&163,696&0.0299\\State B&10,931&0.1402\end{array}\right][/tex]

The seismic activity density is given by the formula;

  • [tex]\displaystyle Seismic \ activity \ density = \mathbf{\frac{Number \ of \ earthquakes}{Area \ of \ land}}[/tex]

Therefore;

Number of earthquakes = Land area × Seismic activity density

Number of earthquakes in State A = 163,696 × 0.0299 ≈ 4894.5104

Number of earthquakes in State B = 10,931 × 0.1402 ≈ 1,532.5262

Which gives;

[tex]\begin{tabular}{|c|c|c|c|}&\underline{Land Area (miles squared)}&\underline{Seismic Activity Density} &\underline{Number of Earthquakes}\\State A&163,696&0.0299&4,894.5104\\State B&10,931&0.1402&\underline{1,532.5262}\\A -B&&&3361.9842\end{array}\right][/tex]

The difference between the number of earthquakes in State A and State B is approximately 3,362 earthquakes.

Therefore;

  • State A had approximately 3,362 more earthquakes than State B

Learn more about earthquakes here:

https://brainly.com/question/1059535

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