Answer:
a.[tex]F=7.83\times 10^{-51} N[/tex]
b.Attractive
Explanation:
We are given that
[tex]F=\frac{GM_1M_2}{R^2}[/tex]
[tex]G=6.67\times 10^{-11} Nm^2/kg^2[/tex]
Mass of an electron,[tex]M_1=9.11\times 10^{-31} kg[/tex]
Mass of proton,[tex]M_2=1836\times 9.11\times 10^{-31} kg[/tex]
Distance between electron and proton,R=[tex]3.602nm=3.602\times 10^{-9} m[/tex]
[tex]1nm=10^{-9} m[/tex]
a.Substitute the values then we get
[tex]F=\frac{6.67\times 10^{-11}\times 9.11\times 10^{-31}\times 1836\times 9.11\times 10^{-31}}{(3.602\times 10^{-9})^2}[/tex]
[tex]F=7.83\times 10^{-51} N[/tex]
b.We know that like charges repel to each other and unlike charges attract to each other.
Proton and electron are unlike charges therefore, the force between proton and electron is attractive.
