Answer:
Step-by-step explanation:
Hello,
[tex]g(n)=80*(\dfrac{3}{4})^n \ So\\g(1)=80*\dfrac{3}{4}=20*3=60 \\\\ and \\\\\dfrac{g(n)}{g(n-1)}=\dfrac{80*(\dfrac{3}{4})^n}{80*(\dfrac{3}{4})^{n-1}}=\dfrac{3}{4} \ so \\\\g(n)=g(n-1)*\dfrac{3}{4}[/tex]
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