Answer: $2.16
Lee watches TV 3 hours per day and TV consumes 200 watts.
Cost of electricity = 12 cents/(1-kilowatt-hour)
200w×3 hours
600 watt-hours
1000 watt-hours=1kwh
1 watt-hours= 1/1000 kwh
600 watt-hours 600/1000=0.6 kwh
0.6×12=7.2cents
1 day=7.2 cents
30 days
7.2×30
216 cents
$2.16
Answer:
The cost of operating a 200-Watt TV 3 hours per day for 30 days is 2.16 dollars.
Step-by-step explanation:
This problem ask us for the total cost associated with electricity consumption in a period of time. Hence, the total cost of energy is obtained by making appropriate conversions, that is:
Cost = Energy consumed x Time x Unit cost
[tex]C = (200\,W) \cdot (30\,days) \cdot \left(3\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h}\right) \cdot \left(\frac{1}{3600000} \,\frac{kWh}{J}\right)\cdot \left(0.12\,\frac{USD}{kWh} \right)[/tex]
[tex]C = 2.16\,USD[/tex]
The cost of operating a 200-Watt TV 3 hours per day for 30 days is 2.16 dollars.
