Here, we are required to write an equation perpendicular to 5x + 6y = 18.
- The equation perpendicular to 5x+6y=18 that passes through the point (10,7) is;
6x - 5y = 25.
- By rearranging 5x+6y=18 to resemble the end of a straight line; y = Mx + c; we have;
Therefore, slope of equation 5x + 6y = 18 is -5/6.
- However, the product of the slopes of 2 perpendicular lines is -1.
Therefore, m1m2 = -1
Therefore, the slope of the required line, m2 is;
m2 = 6/5
Therefore, the equation of a line perpendicular to the equation 5x+6y=18 and passes through the point (10,7) is given as;
6/5 = (y - 7)/(x - 10).
By cross product; we have;
6x - 60 = 5y - 35
6x - 5y = 25.
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