Find local maximum or minimum of the function: f(x)= (x + 1)^2(x - 3) Local maximum point= ( , ) Local maximum value= Local minimum point = ( , ) Local minimum value=

Respuesta :

Answer: Local Max = (-1, 0)

              Local Min = (1, -8)

Step-by-step explanation:

f(x) = (x + 1)² (x - 3)

Step 1: Find the zeros

(x + 1)² = 0 --> x = -1   (multiplicity of 2)

(x - 3) = 0  -->  x = 3

                                   

Step 2: Find the Vertices

x = -1 --> (multiplicity is even which means this is a vertex)

The midpoint between x = -1 and x = 3 is x = 1

Step 3:  Find the Local Max and Local Min

Use the x-value above to find the y-values

f(-1) = 0        because it is a zero

f(1) = (1 + 1)² (1 - 3)

    =    2²(-2)

    =    4(-2)

    =      -8

Conclusion:

(-1, 0) is the Local Max     bigger y-value

(1, -8) is the Local Min      smaller y-value

Answer:

f ( x ) = ( x – 3) 2 – 4; the minimum value is –4

Step-by-step explanation:

Given the function f ( x ) = x 2 – 6 x + 5, write an equivalent form of the function that reveals the minimum or maximum value of the function and state the minimum or maximum value.

f ( x ) = ( x – 3) 2 – 4; the minimum value is –4

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