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3x^2 - 9x + 1 = 0
The quadratic equation is [tex]\frac{-b+/- \sqrt{b^2 -4ac} }{2a}[/tex]
So 'a' is 1
'b' is -9
'c' is 1
Substitute the values into the equation, once with the '+' and once with the '-'
You should get [tex]\frac{9-\sqrt{69} }{6}[/tex] and [tex]\frac{9+\sqrt{69} }{6}[/tex]
To 3 s.f your answers would be 2.88 and 0.116
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- Ally ✧
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