Respuesta :

Space

Answer:

x = -1.47, 1.14

Step-by-step explanation:

Quadratic Formula: [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]

We are given a = 3, b = 1, and c = -5. Simply plug it into the Quadratic Formula:

Step 1: Plug in variables

[tex]x=\frac{-1+/-\sqrt{1^2-4(3)(-5)} }{2(3)}[/tex]

Step 2: Solve

[tex]x=\frac{-1+/-\sqrt{1+60} }{6}[/tex]

[tex]x=\frac{-1+/-\sqrt{61} }{6}[/tex]

Step 3: Plug into calculator to evaluate into decimals

You should get x = -1.46837 and 1.13504

bekkarmahdi702

Answer:

1.13 and -1.46

Step-by-step explanation:

Our quadratic equation is:  3x²+x-5=0

The method we will use is te dicriminant method

let Δ be the discriminant:

  • a= 3
  • b= 1
  • c= -5

Δ = b²-4*a*c

  • Δ= 1²-4*3*(-5)
  • Δ= 1+60
  • Δ=61

61 is a positive number so we have solutions x and x':

  • x= (-b-√Δ)/2*a = (-1-√61)/2*3 = [tex]\frac{-1-\sqrt{61} }{6}[/tex] = -1.46
  • x'= (-b+√Δ)/2*a = (-1+√61)/2*3 =[tex]\frac{-1+\sqrt{61} }{6}[/tex] = 1.13

so the two solutions are :

-1.46 and 1.13

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