Answer:
114.96 pounds at angle 81.76°
Step-by-step explanation:
Let i be the component along x-axis and j be the component along y-axis.
First force that is given is 150 acting at angle 40; [tex]F1 = 150cos170i + 150sin40j = 114.91i +96.42j[/tex]
The second force 100 is acting at angle 170;
[tex]F2 = 100cos170i + 100sin170j = -98.48i + 17.36j[/tex]
We now have the resultant force, which is: [tex]114.91i + 96.42j + (-98.48i + 17.36j) = 16.43i + 113.78j[/tex]
Magnitude of resultant:
[tex]\sqrt{16.43^{2} + 113.78^{2} }[/tex] = 114.96 pounds
Angle it makes with horizontal; inverse tangent of [tex]\frac{(113.78)}{(16.43)}[/tex] = 81.76 degrees
Hope this helps; Brainliest appreciated!
